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&&求解 这个应该怎么处理？求大神求大神？
求解 这个应该怎么处理？求大神求大神？
求解 这个应该怎么处理？
主要问题是rint和rsigma应该怎么处理以及Warning: no match for& & 6 atoms in&&FREE求详细的解决办法，一定要详细，我比较笨如果回答好的，可以加分。
Read instructions and data
** Warning: no match for& & 6 atoms in&&FREE&&**
Data:& & 5623 unique,& && &0 suppressed& &R(int) = 0.0732& &R(sigma) = 0.1145
Systematic absence violations:& & 0& & Bad equivalents:& & 0
&&** Cell contents from UNIT instruction and atom list do not agree **
wR2 =&&0.3732 before cycle& &1 for& &5623 data and& &496 /& &496 parameters
GooF = S =& &&&1.055;& &&&Restrained GooF =& && &1.055&&for& && &0 restraints
Mean shift/esd =& &0.245& & Maximum =& &2.177 for&&U33 C3& && && &at 17:42:07
Max. shift = 0.064 A for C2& && &Max. dU = 0.078 for C3& && && && && && && &
wR2 =&&0.3526 before cycle& &2 for& &5623 data and& &496 /& &496 parameters
GooF = S =& &&&0.982;& &&&Restrained GooF =& && &0.982&&for& && &0 restraints
Mean shift/esd =& &0.192& & Maximum =& &2.186 for&&U22 C2& && && &at 17:42:08
Max. shift = 0.177 A for C2& && &Max. dU =-0.149 for C2& && && && && && && &
wR2 =&&0.3454 before cycle& &3 for& &5623 data and& &496 /& &496 parameters
GooF = S =& &&&0.962;& &&&Restrained GooF =& && &0.962&&for& && &0 restraints
Mean shift/esd =& &0.150& & Maximum =& &2.175 for&&U22 C2& && && &at 17:42:09
Max. shift = 0.133 A for C2& && &Max. dU =-0.279 for C3& && && && && && && &
wR2 =&&0.3393 before cycle& &4 for& &5623 data and& &496 /& &496 parameters
GooF = S =& &&&0.942;& &&&Restrained GooF =& && &0.942&&for& && &0 restraints
Mean shift/esd =& &0.173& & Maximum =&&-2.597 for&&U22 C3& && && &at 17:42:10
Max. shift = 0.170 A for C2& && &Max. dU =-0.413 for C3& && && && && && && &
wR2 =&&0.3378 before cycle& &5 for& &5623 data and& &496 /& &496 parameters
GooF = S =& &&&0.937;& &&&Restrained GooF =& && &0.937&&for& && &0 restraints
Mean shift/esd =& &0.168& & Maximum =& &1.871 for&&U22 C2& && && &at 17:42:12
Max. shift = 0.121 A for C2& && &Max. dU =-0.056 for C2& && && && && && && &
wR2 =&&0.3360 before cycle& &6 for& &5623 data and& &496 /& &496 parameters
GooF = S =& &&&0.931;& &&&Restrained GooF =& && &0.931&&for& && &0 restraints
Mean shift/esd =& &0.157& & Maximum =& &1.460 for&&U22 C2& && && &at 17:42:13
Max. shift = 0.121 A for C2& && &Max. dU =-0.034 for C3& && && && && && && &
wR2 =&&0.3344 before cycle& &7 for& &5623 data and& &496 /& &496 parameters
GooF = S =& &&&0.926;& &&&Restrained GooF =& && &0.926&&for& && &0 restraints
Mean shift/esd =& &0.073& & Maximum =& &1.039 for&&U22 C2& && && &at 17:42:14
Max. shift = 0.082 A for C2& && &Max. dU =-0.045 for C3& && && && && && && &
wR2 =&&0.3344 before cycle& &8 for& &5623 data and& &496 /& &496 parameters
GooF = S =& &&&0.926;& &&&Restrained GooF =& && &0.926&&for& && &0 restraints
Mean shift/esd =& &0.042& & Maximum =& &0.922 for&&U22 C2& && && &at 17:42:15
Max. shift = 0.031 A for C2& && &Max. dU =-0.038 for C3& && && && && && && &
wR2 =&&0.3339 before cycle& &9 for& &5623 data and& &496 /& &496 parameters
GooF = S =& &&&0.924;& &&&Restrained GooF =& && &0.924&&for& && &0 restraints
Mean shift/esd =& &0.047& & Maximum =& &0.910 for&&U22 C2& && && &at 17:42:17
Max. shift = 0.055 A for C2& && &Max. dU =-0.041 for C3& && && && && && && &
wR2 =&&0.3333 before cycle&&10 for& &5623 data and& &496 /& &496 parameters
GooF = S =& &&&0.922;& &&&Restrained GooF =& && &0.922&&for& && &0 restraints
Mean shift/esd =& &0.065& & Maximum =& &0.854 for&&U22 C2& && && &at 17:42:18
Max. shift = 0.088 A for C2& && &Max. dU =-0.047 for C3& && && && && && && &
wR2 =&&0.3325 before cycle&&11 for& &5623 data and& &&&0 /& &496 parameters
GooF = S =& &&&0.920;& &&&Restrained GooF =& && &0.920&&for& && &0 restraints
R1 =&&0.1026 for& &2458 Fo & 4sig(Fo)&&and&&0.1798 for all& &5623 data
wR2 =&&0.3325,&&GooF = S =& &0.920,&&Restrained GooF =& & 0.920&&for all data
R1 =&&0.1799 for& &5623 unique reflections after merging for Fourier
Highest peak& & 0.51&&at&&0.4&&0.8456&&
Deepest hole& &-0.27&&at&&0.2&&0.6067
你好 其他问题怎么解决
这个只是精修给出的结果而已，不用管的，Rint和Rsigma和数据有关，你也改不了，建议多看看书或者多问问师兄师姐。软件熟悉了自然就明白了，
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