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1.(-x)^3*(x^2)^5-(-x4)^2*(-x^6)2.(x^m)^3*(x^3)^m-2(x^2)^3m3.(3ab^2)^2=(-4ab^3)*(-ab)4.(a^nb^3)^3*a^2b^(2n-7)-[a^(n+1)]^2*(ab^2)^n5先化简,后求值.其中x=-1,y=23x^3y^3*(-3分之2x^2y)^2+(-3分之1x^2y)^3*9xy^26.(-3分之4x^2y^2)(-4分之3x^2+xy-5分之2y^2)7.2分之1(x^3-2x^2+3分之2)*(-6x)8.4x^2y^28(x^2-y^2)+(-2xy^2)^21.先化简,后求值。其中x=-3,y=3分之1 3xy^2(-3分之1x^2y+4x^3y^2)-4x^2y(-4分之xy^2)*(-4xy) 2.解方程:6x(1-x)-4x(1-x)=16-2(x^2-2) 3.(y+3)(y-6) 4.(2x+1)(x-1) 5.(ab-2分之1)(ab-3分之1) 6.(x-1)(x-2)(x+3) 7.-(a+3b)(a-5b)
1.原式=-x^3*x^10+x^8*x^6 =-x^13+x^14 =x^14-x^13 2.原式=x^3m*x^3m-2*x^6m =x^6m-2x^6m =-x^6m 3.原式=9a^2b^4+4a^2b^4 =13a^2b^4 4.原式=a^3n*b^9*a^2*b^2(2n-7)-a^(2n+2)a^nb^2n =a^(3n+2)*b^(2n+2)-a^(3n+2)b^2n 5.原式=3x^3y^3*(4/9)*x^4y^2-(1/27)*x^6y^3*9xy^2 =(4/3)*x^7y^5-(1/27)*x^7y^5 =(35/27)*x^7*y^5 =(35/27)*(-1)^7*2^5 =-1120/27 6.原式=(-4/3)*x^2y^2*(-3/4)x^2+(-4/3)*x^2y^2*xy-(-4/3)*x^2y^2*(2/5)y^2) =x^4y^2-(4/3)x^3y^3+(8/15)x^2y^4 7.原式=(1/2)*x^3*(-6x) -(1/2)*2x^2*(-6x) +(1/2)*(2/3)*(-6x) =-3x^4+6x^3-2x 8.原式=4x^4y^28-4x^2y^30+4x^2y^4
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1.原式=-x^3*x^10+x^8*x^6 =-x^13+x^14 =x^14-x^13 2.原式=x^3m*x^3m-2*x^6m =x^6m-2x^6m =-x^6m 3.原式=9a^2b^4+4a^2b^4 =13a^2b^4 4.原式=a^3n*b^9*a^2*b^2(2n-7)-a^(2n+2)...
为什么我算的***不一样呢?你参考一下: 解1:= -x^3*x^10 + 16x^2*x^6
-x^13 +16x^8
= x^3m*x^3m-2*x^6m
= x^6m-2x^6m
9a^2b^4=4a^2b...
.原式=-x^3*x^10+x^8*x^6 =-x^13+x^14 =x^14-x^13 2.原式=x^3m*x^3m-2*x^6m =x^6m-2x^6m =-x^6m 3.原式=9a^2b^4+4a^2b^4 =13a^2b^4 4.原式=a^3n*b^9*a^2*b^2(2n-7)-a^(2n+2)a^nb^2n...
1.原式=-x^3*x^10+x^8*x^6=-x^13+x^14=x^14-x^132.原式=x^3m*x^3m-2*x^6m=x^6m-2x^6m=-x^6m3.原式=9a^2b^4+4a^2b^4=13a^2b^44.原式=a^3n*b^9*a^2*b^2(2n-7)-a^(2n+2)a^nb^2n
解1:= -x^3*x^10 + 16x^2*x^6 = -x^13 +16x^8 2 = x^3m*x^3m-2*x^6m = x^6m-2x^6m = x^6m 3 9a^2b^4=4a^2b^4 = 5a^2b^4 解补充问题: 2 6X-6X^2-4X+4X^2=16-2X^2+4 2X-2X^2=1...
1.原式=-x^3*x^10+x^8*x^6 =-x^13+x^14 =x^14-x^13 2.原式=x^3m*x^3m-2*x^6m =x^6m-2x^6m =-x^6m 3.原式=9a^2b^4+4a^2b^4 =13a^2b^4 4.原式=a^3n*b^9*a^2*b^2(2n-7)-a^(2n+2)...
1.原式=-x^3*x^10+x^8*x^6 =-x^13+x^14 =x^14-x^13 2.原式=x^3m*x^3m-2*x^6m =x^6m-2x^6m =-x^6m 3.原式=9a^2b^4+4a^2b^4 =13a^2b^4 4.原式=a^3n*b^9*a^2*b^2(2n-7)-a^(2n+2)a^nb^2n =a^(3n+2)*b^(2n+2)-a^(3n+2)b^2n
1.(-x)^3*(x^2)^5-(-x4)^2*(-x^6) 2.(x^m)^3*(x^3)^m-2(x^2)^3m 3.(3ab^2)^2=(-4ab^3)*(-ab) 4.(a^nb^3)^3*a^2b^(2n-7)-[a^(n+1)]^2*(ab^2)^n 5先化简,后求值。其中x=-1,y=2 3x^3y^3*(-3分之2x^2y)^2+...
1.原式=-x^3*x^10+x^8*x^6 =-x^13+x^14 =x^14-x^13 2.原式=x^3m*x^3m-2*x^6m =x^6m-2x^6m =-x^6m 3.原式=9a^2b^4+4a^2b^4 =13a^2b^4 4.原式=a^3n*b^9*a^2*b^2(2n-7)-a^(2n+2)a^nb^2...
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(√6-√1/2)-(√24+2√2/3) 4√y^2/x+6√Y^2/9-(7√x+5√x^2) 1/4√3除以5√2*2√12
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为了帮助网友解决“(√6-√1/2)-(√24+2√2/3) 4√y^2/x+6√Y^2/9-(7√x+5√x^2) 1/4√3除以5√2*2√12”相关的问题,学网通过互联网对“(√6-√1/2)-(√24+2√2/3) 4√y^2/x+6√Y^2/9-(7√x+5√x^2) 1/4√3除以5√2*2√12”相关的解决方案进行了整理,用户详细问题包括:RT,我想知道:(√6-√1/2)-(√24+2√2/3) 4√y^2/x+6√Y^2/9-(7√x+5√x^2) 1/4√3除以5√2*2√12,具体解决方案如下:解决方案1:参考
(√6-√1/2)-(√24+2√2/3)
=﹙√6-½√2﹚-﹙2√6+2/3√6﹚
=√6-½√2-2√6-2/3√6
=﹙1-2-2/3﹚√6-½√2
=﹣5/3√6-½√2
4√y^2/x+6√Y^2/9-(7√x+5√x^2)
=4|y|/x√x+2|y|-7√x-5x
1/4√3÷5√2*2√12
=1/4√3×2√12/﹙5√2﹚
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