Error 401--Unauthorized
Error 401--Unauthorized
From RFC 2068 Hypertext Transfer Protocol -- HTTP/1.1:
10.4.2 401 Unauthorized
The request requires user authentication. The response MUST include a WWW-Authenticate header field (section 14.46) containing a challenge applicable to the requested resource. The client MAY repeat the request with a suitable Authorization header field (section 14.8). If the request already included Authorization credentials, then the 401 response indicates that authorization has been refused for those credentials. If the 401 response contains the same challenge as the prior response, and the user agent has already attempted authentication at least once, then the user SHOULD be presented the entity that was given in the response, since that entity MAY include relevant diagnostic information. HTTP access authentication is explained in section 11.您当前位置： >
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***验证
稿件来源: 阳光企业网站管理系统
& 撰稿作者: 太阳光
& 发表日期:
& 阅读次数: 71
& 查看权限: 游客查看
原网上摘录的验证不正确，故在此更正并做了15位与18位***兼容。关键验证了字符、出生日期与尾数。
&javascript版本：
function isIdCard(arrIdCard){
//支持15/18位***验证
var IdCard=arrIdCard.toString().toUpperCase();
if(!/^\d{17}(\d|X)$/i.test(IdCard)&&!/^\d{15}$/i.test(IdCard)){
if(IdCard.length==18){
var sigma = 0;
var a = new Array(7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2 );
var w = new Array(&1&, &0&, &X&, &9&, &8&, &7&, &6&, &5&, &4&, &3&, &2&);
for (var i = 0; i & 17; i++) {
sigma += parseInt(IdCard.substring(i, i + 1)) * a[i];
if (IdCard.substring(17) != w[sigma % 11]) {
birth=IdCard.substring(6, 10)+&/&+IdCard.substring(10, 12)+&/&+IdCard.substring(12, 14);
birth=&19&+IdCard.substring(6, 8)+&/&+IdCard.substring(8, 10)+&/&+IdCard.substring(10, 12);
var date=new Date(birth);
var getDate=date.getFullYear()+&/&+(&0&+(date.getMonth()+1)).slice(-2)+&/&+(&0&+date.getDate()).slice(-2);
return getDate==
推荐另一种方法：
var checkCardId = function (card) {
card=card+&&;//比toString()好使;
if(!/^((1[1-5]|2[1-3]|3[1-7]|4[1-6]|5[0-4]|6[1-5])[0-9]{4})(([1|2][0-9]{3}[0|1][0-9][0-3][0-9][0-9]{3}[X0-9])|([0-9]{2}[0|1][0-9][0-3][0-9][0-9]{3}))$/i.test(card)){
var j = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2];
var k = ['1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'];
var n= 0,i;
if (15==card.length){ //15位自动转18位
card = card.substring(0, 6) + '19' + card.substring(6);
for (i = 0; i & 17; i++) {
n += j[i]*card.substring(i, i+1);
card += k[n % 11];
var b=card.substring(6, 10)+&/&+card.substring(10, 12)+&/&+card.substring(12, 14);
var t=new Date(b);
var d=t.getFullYear()+&/&+(&0&+(t.getMonth()+1)).slice(-2)+&/&+(&0&+t.getDate()).slice(-2);
for (i = 0; i & 17; i++) {
n += j[i] * card.substring(i,i+1);
var l=isNaN(card.slice(-1))?&X&:card.slice(-1);
return l==k[n % 11]&&d==b;
java版本：
public static boolean isIdCard1(String arrIdCard){
//支持15/18位***验证
String idCard= arrIdCard.toUpperCase();
String test1 = &[0-9]{17}([0-9]|X)&;
String test2 = &[0-9]{15}&;
Pattern pattern1 = pile(test1);
Pattern pattern2 = pile(test2);
Matcher isNum1 = pattern1.matcher(idCard);
Matcher isNum2 = pattern2.matcher(idCard);
if(!isNum1.matches() && !isNum2.matches()){
if(idCard.length() == 18){
int sigma = 0;
Integer[] a = { 7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2 };
String[] w = { &1&, &0&, &X&, &9&, &8&, &7&, &6&, &5&, &4&, &3&, &2& };
for (int i = 0; i & 17; i++) {
int ai = Integer.parseInt(idCard.substring(i, i + 1));
int wi = a[i];
sigma += ai *
int number = sigma % 11;
String check_number = w[number];
if (!idCard.substring(17).equals(check_number)) {
birth = idCard.substring(6, 10)+&-&+idCard.substring(10, 12)+&-&+idCard.substring(12, 14);
birth=&19&+idCard.substring(6, 8)+&-&+idCard.substring(8, 10)+&-&+idCard.substring(10, 12);
Date birDate = Utils.convert(birth);
String birStr2 = (birDate.getYear()+1900)+&-&+(birDate.getMonth()+1)+&-&+birDate.getDate();
if(!birth.equals(birStr2)){
======================== 18位***检测
function&checkCardId(card)&{
&&&&card&=&card.toString().toUpperCase();
&&&&var&arr&=&card.match(/^\d{6}(\d{4})(\d{2})(\d{2})\d{3}([X0-9])$/);
&&&&if(!arr)&return&
&&&&var&j&=&[7,&9,&10,&5,&8,&4,&2,&1,&6,&3,&7,&9,&10,&5,&8,&4,&2];
&&&&var&k&=&['1',&'0',&'X',&'9',&'8',&'7',&'6',&'5',&'4',&'3',&'2'];
&&&&var&t&=&new&Date(arr[1]&+&/&+&arr[2]&+&/&+&arr[3]);
&&&&t&=&t.getMonth()&+&1&==&arr[2]&&&&t.getDate()&==&arr[3];
&&&&for&(var&i&=&0,n&=&0;&i&&&17;&i++)&{
&&&&&&&&n&+=&j[i]&*&card.substring(i,i+1);
&&&&return&t&&&&arr[4]&==&k[n&%&11];
关键词: js,***验证 & 编辑时间:
3高兴0支持0搞笑0不解0谎言0***稿0震惊0无奈0无聊0反对0愤怒
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