工具类（3）
package com.step.
import java.io.IOE
import java.net.URLD
import java.util.ArrayL
import java.util.L
import org.apache.http.HttpR
import org.apache.http.HttpS
import org.apache.http.NameValueP
import org.apache.http.client.ClientProtocolE
import org.apache.http.client.HttpC
import org.apache.http.client.entity.UrlEncodedFormE
import org.apache.http.client.methods.HttpG
import org.apache.http.client.methods.HttpP
import org.apache.http.entity.StringE
import org.apache.http.impl.client.DefaultHttpC
import org.apache.http.message.BasicNameValueP
import org.apache.http.util.EntityU
import com.alibaba.fastjson.JSONO
* 发送HTTP请求
* @author mlu
public class HttpUtils {
* 发送post请求--用于接口接收的参数为JSON字符串
* @param url 请求地址
* @param params json格式的字符串
public static String httpPost(String url, String params){
String result =
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
* 发送json字符串，这两句需要设置
httpPost.addHeader(&Content-type&,&application/ charset=utf-8&);
httpPost.setHeader(&Accept&, &application/json&);
httpPost.setEntity(new StringEntity(params, &UTF-8&));
HttpResponse response = httpClient.execute(httpPost);
int statusCode = response.getStatusLine().getStatusCode();
if (statusCode == HttpStatus.SC_OK) {
// Read the response body
result = EntityUtils.toString(response.getEntity(),&UTF-8&);
} catch (Exception e) {
e.printStackTrace();
* 发送post请求--用于接口接收的参数为键值对
* @param url 请求地址
* @param nameValuePairs 键值对
public static String httpPost(String url, List&NameValuePair& nameValuePairs) {
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
String strResult = &&;
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairs, &UTF-8&));
HttpResponse response = httpClient.execute(httpPost);
if (response.getStatusLine().getStatusCode() == 200) {
/* 读返回数据 */
strResult = EntityUtils.toString(response.getEntity());
// System.out.println(&conResult:&+conResult);
strResult += &发送失败:& + response.getStatusLine().getStatusCode();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
return strR
public static String httpGet(String url, List&NameValuePair& nameValuePairs){
HttpClient httpClient = new DefaultHttpClient();
String sb = &&;
String result = &&;
for(NameValuePair nvp:nameValuePairs){
sb += nvp.getName()+&=&+nvp.getValue()+&&&;
sb = sb.substring(0,sb.length()-1);
sb = URLDecoder.decode(sb, &UTF-8&);
HttpGet httpGet = new HttpGet(url+&?&+sb);
HttpResponse response = httpClient.execute(httpGet);
if (response.getStatusLine().getStatusCode() == 200) {
/* 读返回数据 */
result = EntityUtils.toString(response.getEntity());
result += &发送失败:& + response.getStatusLine().getStatusCode();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
public static void main(String[] args) {
String url = &http://10.140.8.56/gd_fssc/rest/fsscService/getStaffInfo&;
String url2 = &http://localhost:8080/eshore-app-backframe-web/interface/getJson&;
// 发送 POST 请求
JSONObject json = new JSONObject();
json.put(&number&, &@GD&);
httpPost(url,json.toString());
List&NameValuePair& nameValuePairs = new ArrayList&&();
nameValuePairs.add(new BasicNameValuePair(&method&, &login&));
httpGet(url2,nameValuePairs);
引用的jar包：
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评论：25条iOS 解决iOS 9下的http请求发送失败问题
来源：博客园
iOS9中 因为系统要求所有的请求都必须使用 https, 所以发送http请求会失败,如果想让程序能够兼容http请求 在info.plist中添加以下代码: 这里需要做的是右键info.plist文件, 显示源代码, 在源代码中进行添加下面这几行代码.
NSAppTransportSecurity
NSAllowsArbitraryLoads
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